15=x^2-3x^2+5x

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Solution for 15=x^2-3x^2+5x equation: 



15=x^2-3x^2+5x

We move all terms to the left:

15-(x^2-3x^2+5x)=0

We get rid of parentheses

-x^2+3x^2-5x+15=0

We add all the numbers together, and all the variables

2x^2-5x+15=0

a = 2; b = -5; c = +15;
Δ = b2-4ac
Δ = -52-4·2·15
Δ = -95
Delta is less than zero, so there is no solution for the equation

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